Elegy%

Combinatorial Complexity of Elegy%

When randomizing the order of Elegy%, the number of possible unique permutations in which we can rescue the grubs is given by:

44! = 44 x 43 x 42 x ... x 2 x 1

Note: City Collector All Grubs counts as 3 grubs in terms of points, it is treated as a single event in the permutation sequence. Therefore, the total number of points is still 44.

This factorial operation results in approximately:

44! = ~2.66 x 1054

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