Elegy%

Elegy%

Combinatorial Complexity of Elegy%

When randomizing the order of Elegy%, the number of possible unique permutations in which we can rescue the grubs is given by:

44! = 44 × 43 × 42 × … × 2 × 1

City Collector All Grubs counts as 3 grubs in terms of points, but it is treated as a single event in the permutation sequence. Therefore, the total number of points is still 44.

The total number of possible permutations is:

44! ≈ 2.66 × 1054

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